In $\triangle A B C, A D \perp B C$ at D and AE is the bisector of $\angle A$. If $\angle B=62^{\circ}$ and $\angle C=36^{\circ}$, then what is the measure of $\angle D A E$ ?

13°

When angle bisector and perpendicular bisector are given for a triangle and the angle made by them is asked then in that case,

Angle made = \(\frac{Difference}{2}\)

= \(\angle\)DAE = (\({62}^\circ\) - \({36}^\circ\))/2

= \(\angle\)DAE = \({26}^\circ\)/2

= \(\angle\)DAE = \({13}^\circ\)

Therefore, \(\angle\)DAE is \({13}^\circ\).