In $\triangle A B C, A D \perp B C$ at D and AE is the bisector of $\angle A$. If $\angle B=62^{\circ}$ and $\angle C=36^{\circ}$, then what is the measure of $\angle D A E$ ?
Answer & explanation
Correct answer: option 4
When angle bisector and perpendicular bisector are given for a triangle and the angle made by them is asked then in that case,
Angle made = \(\frac{Difference}{2}\)
= \(\angle\)DAE = (\({62}^\circ\) - \({36}^\circ\))/2
= \(\angle\)DAE = \({26}^\circ\)/2
= \(\angle\)DAE = \({13}^\circ\)
Therefore, \(\angle\)DAE is \({13}^\circ\).