Match List I with List II

Choose the correct answer from the options given below:

A-II, B-IV, C-I, D-III

The correct answer is option 1. A-II, B-IV, C-I, D-III.

Let us look at the different molecules and their bonding:

A. Terylene: Terylene is a type of polyester, which is a polymer composed of repeating units linked together by ester linkages. These ester linkages \((-COO-)\) are formed between the carboxyl (-COOH) groups of one monomer and the hydroxyl \((-OH)\) groups of another monomer during the polymerization process.

B. Nylon: Nylon is a synthetic polymer known as a polyamide, which is formed by the condensation polymerization of monomers containing both carboxyl \((-COOH)\) and amino \((-NH_2)\) groups. The amide linkages \((-CONH-)\) are formed between the carboxyl group of one monomer and the amino group of another monomer

C. Cellulose: Cellulose is a polysaccharide found in the cell walls of plants and is composed of repeating glucose monomers linked together by glycosidic linkages \((-C-O-C-)\). These linkages are formed between the anomeric carbon atom of one glucose molecule and the hydroxyl group of another glucose molecule during polymerization.

D. RNA: RNA (ribonucleic acid) is a nucleic acid composed of nucleotide monomers. The backbone of RNA is formed by phosphodiester linkages \((-PO_2-)\) between the 3' carbon of one nucleotide and the 5' carbon of the next nucleotide in the chain.

Therefore, the correct matches are:

A-II (Terylene contains ester linkages),

B-IV (Nylon contains amide linkages),

C-I (Cellulose contains glycosidic linkages),

D-III (RNA contains phosphodiester linkages).

So, option 1. A-II, B-IV, C-I, D-III is correct.