Match List I with List II
| LIST I | LIST II |
| A. Terylene | I. Glycosidic linkage |
| B. Nylon | II. Ester linkage |
| C. Cellulose | III. Phosphodiester linkage |
| D. RNA | IV. Amide linkage |
Choose the correct answer from the options given below:
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → A-II, B-IV, C-I, D-III
A. Terylene — This matches II. Ester linkage. A polyester of ethylene glycol and terephthalic acid.
B. Nylon — This matches IV. Amide linkage. A polyamide, e.g. nylon 6,6 from hexamethylenediamine and adipic acid.
C. Cellulose — This matches I. Glycosidic linkage. β-D-glucose units joined C1–C4 through oxygen.
D. RNA — This matches III. Phosphodiester linkage. Nucleotides joined between the 5′ and 3′ carbons of the sugar.