How many unpaired electrons are present in the high spin form of [CoF6]3- complex and which metal orbitals are used in bonding?
Answer & explanation
Correct answer: option 3
The correct answer is option 3. 4 unpaired electrons and 4s, 4p and 4d orbitals to give sp3d2 hybridisation.
The atomic number of the central metal ion, \(Co\) is 27.
The electronic configuration of the central metal ion is
\(_{27}Co = [_{18}Ar] 4s^2 3d^7\)
Let the oxidation of the central metal ion be \(x\). Then
\(x + 6(-1) = -3\)
or, \(x - 6 = -3\)
or, \(x = +3\)
