Practicing Success

Target Exam

CUET

Subject

Chemistry

Chapter

Inorganic: Coordination Compounds

Question:

How many unpaired electrons are present in the high spin form of [CoF6]3- complex and which metal orbitals are used in bonding?

Options:

0 unpaired electrons and 4s, 4p and 4d orbitals to give sp3d2 hybridisation.

0 unpaired electrons and 3d, 4s and 4p orbitals to give d2sp3 hybridisation.

4 unpaired electrons and 4s, 4p and 4d orbitals to give sp3d2 hybridisation.

4 unpaired electrons and 3d, 4s and 4p orbitals to give d2sp3 hybridisation.

Correct Answer:

4 unpaired electrons and 4s, 4p and 4d orbitals to give sp3d2 hybridisation.

Explanation:

The correct answer is option 3. 4 unpaired electrons and 4s, 4p and 4d orbitals to give sp3d2 hybridisation.

The atomic number of the central metal ion, \(Co\) is 27.

The electronic configuration of the central metal ion is

\(_{27}Co = [_{18}Ar] 4s^2 3d^7\)

Let the oxidation of the central metal ion be \(x\). Then

\(x + 6(-1) = -3\)

or, \(x - 6 = -3\)

or, \(x = +3\)