Practicing Success

Target Exam

CUET

Subject

Biology

Chapter

Molecular Basis of Inheritance

Question:

Match List - I with List - II.

List - I List - II
(A) RNA Polymerase II (I) 28 srRNA
(B) RNA Polymerase I (II) hn RNA
(C) Ribozome (III) 5 srRNA
(D) RNA Polymerase III (IV) 23 srRNA in bacteria

Choose the correct answer from the options given below:

Options:

(A)-(III), (B)-(II), (C)-(I), (D)-(IV)

(A)-(II), (B)-(IV), (C)-(III), (D)-(I)

(A)-(II), (B)-(I), (C)-(IV), (D)-(III)

(A)-(IV), (B)-(III), (C)-(II), (D)-(I)

Correct Answer:

(A)-(II), (B)-(I), (C)-(IV), (D)-(III)

Explanation:

The correct answer is Option (3) - (A)-(II), (B)-(I), (C)-(IV), (D)-(III)

List - I List - II
(A) RNA Polymerase II (II) hn RNA 
(B) RNA Polymerase I (I) 28 srRNA
(C) Ribozome (IV) 23 srRNA in bacteria
(D) RNA Polymerase III (III) 5 srRNA

In eukaryotes: 

There are at least three RNA polymerases in the nucleus (in addition to the RNA polymerase found in the organelles). There is a clear cut division of labour.

The RNA polymerase I transcribes rRNAs (28S, 18S, and 5.8S),

whereas the RNA polymerase III is responsible for transcription of tRNA, 5srRNA, and snRNAs (small nuclear RNAs).

The RNA polymerase II transcribes precursor of mRNA, the heterogeneous nuclear RNA (hnRNA).

The 23s rRNA is a structural RNA present in the ribosomes and a ribozyme that catalyses the formation of peptide bonds during translation in bacteria (prokaryotes).