A bag contain 8 blue and 12 green balls. Two balls are drawn in succession without replacement. The probability that first is blue and second is green is

$\frac{24}{95}$

The correct answer is Option (4) → $\frac{24}{95}$ **

Total balls = $8 + 12 = 20$

Probability(first blue) = $\frac{8}{20}$

After one blue is removed, remaining: 7 blue, 12 green → total 19

Probability(second green) = $\frac{12}{19}$

Required probability = $\frac{8}{20}\times\frac{12}{19}=\frac{96}{380}=\frac{24}{95}$