Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section A

Chapter

Differential Equations

Question:

Match List-I with List-II.

List-I List-II
Differential equation Integrating Factor (I.F)
(A) $\frac{dy}{dx}-\frac{y}{x}=2x$ (I) $x^2-1$
(B) $\frac{dy}{dx}+\left(\frac{2x}{x^2-1}\right)y=\frac{2}{(x^2-1)^2}$ (II) $\frac{1}{x}$
(C) $\frac{dy}{dx}-\left(\frac{x}{1-x^2}\right)y=\frac{1}{1-x^2}$ (III) $\frac{1}{x}$
(D) $\frac{dy}{dx}+\frac{2xy}{1+x^2}=\frac{cotx}{1+x^2}$ (IV) $1+x^2$

Choose the correct answer from the options given below :

Options:

(A)-(III), (B)-(I),(C)-(IV),(D)-(II)

(A)-(III), (B)-(IV),(C)-(I),(D)-(II)

(A)-(III), (B)-(II), (C)-(I), (D)-(IV)

(A)-(III), (B)-(I), (C)-(II), (D)-(IV)

Correct Answer:

(A)-(III), (B)-(I), (C)-(II), (D)-(IV)

Explanation:

The correct answer is Option (4) → (A)-(III), (B)-(I), (C)-(II), (D)-(IV)

(A) $I.F.=e^{\int -\frac{1}{x}dx}=e^{-\log x}=\frac{1}{x}$ (III)

(B) $I.F.=e^{\int\frac{2x}{x^2-1}dx}=e^{\log|x^2-1|}=x^2-1$ (I)

(C) $I.F.=e^{\int\frac{-x}{1-x^2}dx}=e^{\frac{1}{2}\log|1-x^2|}=\sqrt{1-x^2}$ (II)

(D) $I.F.=e^{\int\frac{2x}{1+x^2}dx}=e^{\log|1+x^2|}=1+x^2$ (IV)