If 2 sec 2θ = tan Ø + cot Ø, then find value of ( θ + Ø) ?
Answer & explanation
Correct answer: option 2
Here,
⇒ 2 sec 2θ = tan Ø + cot Ø = 2 cosec (2Ø)
⇒ 2 sec 2θ = 2 cosec 2Ø
⇒ sec 2θ = cosec 2Ø,
therefore,
⇒ 2θ + 2Ø = 90°
⇒ θ + Ø = 45°
If 2 sec 2θ = tan Ø + cot Ø, then find value of ( θ + Ø) ?
Correct answer: option 2
Here,
⇒ 2 sec 2θ = tan Ø + cot Ø = 2 cosec (2Ø)
⇒ 2 sec 2θ = 2 cosec 2Ø
⇒ sec 2θ = cosec 2Ø,
therefore,
⇒ 2θ + 2Ø = 90°
⇒ θ + Ø = 45°