Practicing Success
Practicing Success
CUET Preparation Today
The value of the integral $\int\limits_{\log _e 2}^{\log _e 3} \frac{e^{2 x}-1}{e^{2 x}+1} d x$ is: |
$\log _e 3$ $\log _e 4 - \log _e 3$ $\log _e 9-\log _e 4$ $\log _e 3-\log _e 2$ |
$\log _e 4 - \log _e 3$ |
The correct answer is Option (2) → $\log _e 4 - \log _e 3$ |
