If the magnetic field strength is made half, how will a charged particle perpendicularly projected into the field change its radius?
Answer & explanation
Correct answer: option 2
The correct answer is Option (B) → The radius will become double.
Radius of the path $(R) = \frac{mv}{qB}$
$⇒R∝\frac{1}{B}$ [Inversely proportional]
∴ if magnetic field is made half, Radius will become twice.