Practicing Success
The diagonals of a rhombus are 24 cm and 32 cm, then perimeter is? |
76 cm 80 cm 84 cm 72 cm |
80 cm |
The diagonal of a rhombus bisect each other perpendicularly. Therefore, in Δ AOB: ⇒\(\angle\)AOB = 90°, AO = \(\frac{AC}{2}\) = 12 and BO = \(\frac{BD}{2}\) = 16 So, ⇒ AB2 = OA2 + OB2 ⇒ AB2 = (12)2 + (16)2 ⇒ AB2 = 144 + 256 = 400 ⇒ AB = 20 ⇒ Perimeter = 4 × side = 4 × 20 = 80 cm |