$sin^4θ+ cos^4θ$ in terms of sinθ can be written as:
Answer & explanation
Correct answer: option 4
sin4θ+ cos4θ
we know , cos2θ = 1 - sin2θ
= sin4θ + ( 1 - sin2θ )2
= sin4θ + 1 + sin4θ - 2sin2θ
= 2sin4θ - 2sin2θ + 1
$sin^4θ+ cos^4θ$ in terms of sinθ can be written as:
Correct answer: option 4
sin4θ+ cos4θ
we know , cos2θ = 1 - sin2θ
= sin4θ + ( 1 - sin2θ )2
= sin4θ + 1 + sin4θ - 2sin2θ
= 2sin4θ - 2sin2θ + 1