Practicing Success
Practicing Success
CUET Preparation Today
$sin^4θ+ cos^4θ$ in terms of sinθ can be written as: |
$2sin^4θ+2sin^2θ-1$ $2sin^4θ-2sin^2θ$ $2sin^4θ-2sin^2θ-1$ $2sin^4θ-2sin^2θ+1$ |
$2sin^4θ-2sin^2θ+1$ |
sin4θ+ cos4θ we know , cos2θ = 1 - sin2θ = sin4θ + ( 1 - sin2θ )2 = sin4θ + 1 + sin4θ - 2sin2θ = 2sin4θ - 2sin2θ + 1 |
