A certain number of men completed a work in 60 days. If there were 8 more men, work could have been completed in 10 less days. How many men were there? |
20 30 40 50 |
40 |
The correct answer is Option (3) → 40 Let Men Required to complete the work be x We know that, Men required, M ∝ \(\frac{1}{Number of Days, D}\) Thus, MD = Constant M1 D1 = M2 D2 x × 60 = (x+8) × (60-10) 60 x = 50 x + 400 ⇒ Men Required, x = 40
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