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$y=\log _{a}\left(x^2\right)$, then $\frac{d y}{d x}$ at x = e, is |
2e 1/e 2/e none of these |
none of these |
$y=\log _a x^2=\frac{d y}{d x}=\frac{\log x^2}{\log _e a}=\frac{1}{x^2} \times \frac{2 x}{\log _e a}=\frac{2}{x \log _e a}$ Hence (4) is correct answer. |
