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CUET
Physics
Nuclei
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$ N = N_0 e^{-\lambda t} = \frac{N_0}{10}$
$ \lambda t = ln10$
$ t = \frac{ln10}{\lambda} = \frac{ln10 t_{1/2}}{ln 2}$
$ \Rightarrow t = 12.62 days$
