PA is a tangent at A to a circle with centre O. If \(\angle APO=28^\circ\), what is the measure of \(\angle AOP\)?
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → 62°
The tangent is perpendicular to the radius at the point of contact, so \(\angle OAP=90^\circ\); the three angles of \(\triangle OAP\) add up to \(180^\circ\).
\(\angle OAP=90^\circ\), \(\angle APO=28^\circ\)
\(\angle AOP=180^\circ-90^\circ-28^\circ=62^\circ\)
