A resistor R and an inductor L are connected in series to a 24 V, 50 Hz supply. A current of 1 A flows through the circuit. If the current differs in phase from the applied voltage by 60°, the value of impedance in the circuit is

24 Ω

The correct answer is Option (1) → 24 Ω

Given:

• Voltage V=24 V
• Current I=1 A

Impedance: Z = V / I

                    = 24/ 1 = 24

About the 60° phase difference:

• This is not required to find impedance.
  It is used only if we need:

  • Resistance R
  • Inductive reactance Xₗ

Note: There was an error in the original question, due to which it was dropped by NTA. However, for the benefit of students and to provide additional practice, the question has been suitably modified to make it correct.