Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Trigonometry

Question:

Solve \(\frac{32cos^610° - 48cos^410° + 18cos^210° - 1}{4sin10° cos10° sin50° cos50° sin70° cos70°}\)

Options:

\(\frac{8}{\sqrt {3}}\)

8\(\sqrt {3}\)

\(\frac{4}{\sqrt {3}}\)

4\(\sqrt {3}\)

Correct Answer:

\(\frac{8}{\sqrt {3}}\)

Explanation:

\(\frac{2(cos^610° - 24cos^410° + 9cos10° ) - 1}{4 × \frac{1}{4}sin 3 × 10° × \frac{1}{4} × cos3 × 10° }\)

⇒ \(\frac{2 (4cos^310° - 3cos10° )^2 - 1}{4 × \frac{1}{4} × \frac{1}{2} × \frac{1}{4} × \frac{\sqrt {3}}{2} }\)

(cos3θ = 4cos3 θ - 3cosθ)

⇒ \(\frac{2 × (cos3 θ)^2 - 1}{\frac{\sqrt {3}}{16}}\)

⇒ \(\frac{2 × cos^230 - 1}{\frac{\sqrt {3}}{16}}\)

⇒ \(\frac{2 × \frac{3}{4}- 1}{\frac{\sqrt {3}}{16}}\)

 = \(\frac{8}{\sqrt {3}}\)