Practicing Success
If x2 - 11x + 1= 0 and x > 1, then the value of x2 + \(\frac{1}{x^2}\) will be: |
121 67 119 134 |
119 |
If x2 - 11x + 1= 0 Divide by x on both sides, x + \(\frac{1}{x}\) =11 x2 + \(\frac{1}{x^2}\) = 112 - 2 = 119
If x + \(\frac{1}{x}\) = a then, x2 + \(\frac{1}{x^2}\) = a2 - 2 |