A T.V. tower has a height of 150 m. The area of the region covered, the T.V. broadcast is (radius of earth = $6.4 × 10^6 m$) -

$9.6 π × 10^8 m^2$ $19.2π × 10^8 m^2$ $19.2 π × 10^7 m^2$ $1.92π × 10^3 km^2$

$19.2π × 10^8 m^2$

Area of the region covered for broadcasting $= πd^2 = π(2hR)$ $= π × 2 × 150 × 6.4 × 10^6$ $= π × 300 × 6.4 × 10^6$ $= 19.2 × π × 108 m^2$