If [A]_3×2 [B]_x×y = [C]_3×1, then:

The correct answer is Option (2) - x = 2, y = 1

$[A]_{3×2} [B]_{x×y} = [C]_{3×1}$

order (C) = 3 × y

so $y=1$

$x=2$  (for multiplication no of rows of first matrix = no. of rows of second matrix)