If $[A]_{3×2} [B]_{x×y} = [C]_{3×1}$, then: |
x = 1, y = 3 x = 2, y = 1 x = 3, y = 3 x = 3, y = 1 |
x = 2, y = 1 |
The correct answer is Option (2) - x = 2, y = 1 $[A]_{3×2} [B]_{x×y} = [C]_{3×1}$ order (C) = 3 × y so $y=1$ $x=2$ (for multiplication no of rows of first matrix = no. of rows of second matrix) |