If x+y = 7 find (\(\frac{1}{{x}^{3}}\)

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Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Algebra

Question:

If x+y = 7

find (\(\frac{1}{{x}^{3}}\) + \(\frac{1}{{y}^{3}}\))

Options:

0.543

0.131

0.133

0.453

Correct Answer:

0.133

Explanation:

Put x = 5, y = 2 [Because these value are satisfying the equations]

⇒ \(\frac{1}{({5}^{3})}\) + \(\frac{1}{({2}^{3})}\) = \(\frac{125+8}{1000}\) = 0.133