Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Numerical Ability

Topic

Percentages

Question:

The population of a town increases at a rate of 10% for every year. If the present population is 12100, find the population two years ago.

 

Options:

11000

9800

10000

10120

Correct Answer:

10000

Explanation:

Formulae of net effect:

x + y + \(\frac{xy }{100 }\)

10 + 10 + \(\frac{100 }{100 }\) = 21%

According to question, 

Population at present (after increase of 10% every year) = 12100

Population 2 years ago = \(\frac{12100 }{121 }\) x 100 = 10000