Practicing Success
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CUET Preparation Today
The electric field vector oscillates according to the equation $\vec E = 4\sin[1.8y+(5.4×10^6)t]\hat k$. The equation of magnetic field vector is: |
$\vec B=1.33×10^{-8} \sin[1.8y +(5.4×10^6)t]\hat i$ $\vec B=4\sin[1.8y+(5.4×10^4)i]\hat j$ $\vec B=1.33×10^{-8} \sin[1.8y +(5.4×10^6)t]\hat k$ $\vec B=5\sin[1.8y+(5.4×10^4)i]\hat j$ |
$\vec B=1.33×10^{-8} \sin[1.8y +(5.4×10^6)t]\hat i$ |
The correct answer is Option (1) → $\vec B=1.33×10^{-8} \sin[1.8y +(5.4×10^6)t]\hat i$ |
