The electric field vector oscillates according to the equation $\vec E = 4\sin[1.8y+(5.4×10^6)t]\hat k$. The equation of magnetic field vector is:
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → $\vec B=1.33×10^{-8} \sin[1.8y +(5.4×10^6)t]\hat i$
The given vector field is,
$\vec E = 4\sin(1.8y+(5.4×10^6)t)\hat k$
and,
$B_0=\frac{E_0}{C}=\frac{4}{3×10^8}\sin(1.8y+(5.4×10^6)t)\hat i$
$=(1.33×10^{-8})\sin(1.8y +(5.4×10^6)t)\hat i$