If $ K + \frac{1}{K} = - 3, $ then what is the value of $(\frac{K^6+1}{K^3})+(\frac{K64+1}{K^2}) ?$
Answer & explanation
Correct answer: option 2
A detailed explanation for this question is coming soon.
If $ K + \frac{1}{K} = - 3, $ then what is the value of $(\frac{K^6+1}{K^3})+(\frac{K64+1}{K^2}) ?$
Correct answer: option 2
A detailed explanation for this question is coming soon.