Which is the smallest natural number by which 243 must be multiplied to make the product a perfect cube?

3 9 8 7

3

For a number to be a perfect cube, its powers of prime factors must have multiples of 3. After prime factorization, we get: 243 = 3 × 3 × 3 × 3 × 3 = 243 i.e. 35 In order to make this number a perfect cube, we will multiply 3 once so that the power becomes 36 i.e. power with a multiple of 3.