The system of equations
\(x + y + z = 2\)
\(2x + 3y + z = 5\)
\(3x + 4y + 2z = 9\)
has
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → no solution
Write the system as AX = B with
\( \displaystyle A = \begin{bmatrix}1 & 1 & 1\\ 2 & 3 & 1\\ 3 & 4 & 2\end{bmatrix},\quad B = \begin{bmatrix}2\\ 5\\ 9\end{bmatrix} \)
Expanding along the first row:
\( |A| = 1(6 - 4) - 1(4 - 3) + 1(8 - 9) \)
\( = 2 - 1 - 1 = 0 \)
So there is no unique solution, and we look at \((\mathrm{adj}\,A)B\). The cofactors are
\( C_{11} = 2,\ C_{12} = -1,\ C_{13} = -1 \)
\( C_{21} = 2,\ C_{22} = -1,\ C_{23} = -1 \)
\( C_{31} = -2,\ C_{32} = 1,\ C_{33} = 1 \)
so
\( \displaystyle (\mathrm{adj}\,A)B = \begin{bmatrix}2 & 2 & -2\\ -1 & -1 & 1\\ -1 & -1 & 1\end{bmatrix}\begin{bmatrix}2\\ 5\\ 9\end{bmatrix} \)
\( \displaystyle = \begin{bmatrix}4 + 10 - 18\\ -2 - 5 + 9\\ -2 - 5 + 9\end{bmatrix} = \begin{bmatrix}-4\\ 2\\ 2\end{bmatrix} \)
Since \(|A| = 0\) and \((\mathrm{adj}\,A)B \ne O\), the system is inconsistent: it has no solution.
Check: adding the first two equations gives \(3x + 4y + 2z = 7\), while the third equation says the same expression equals 9.