Molarity of H₂SO₄ solution is 18 and it's density is 1.8 g/ml. What is the molality of solution?

500

18 moles of H₂SO₄ are present in 1000 ml of solution.

density of solution = 1.8 g/ml

density of solution = \(\frac{\text{mass of solution}}{\text{volume of solution}}\)

1.8 = \(\frac{\text{mass of solution}}{1000}\)

mass of solution = 1.8 x 1000 = 1800 g

no of moles = \(\frac{\text{given mass of solute}}{\text{molecular mass of solute}}\)

18 = \(\frac{\text{given mass of solute}}{98}\)

given mass of solute = 18 x 98 = 1764 g

mass of solvent = 1800 - 1764 = 36 g

m = \(\frac{\text{no of moles of solute}}{\text{mass of solvent (in g)}}\) x 1000

m = \(\frac{18}{36}\) x 1000

m = 500