Molarity of H2SO4 solution is 18 and it's density is 1.8 g/ml. What is the molality of solution?
Answer & explanation
Correct answer: option 3
18 moles of H2SO4 are present in 1000 ml of solution.
density of solution = 1.8 g/ml
density of solution = \(\frac{\text{mass of solution}}{\text{volume of solution}}\)
1.8 = \(\frac{\text{mass of solution}}{1000}\)
mass of solution = 1.8 x 1000 = 1800 g
no of moles = \(\frac{\text{given mass of solute}}{\text{molecular mass of solute}}\)
18 = \(\frac{\text{given mass of solute}}{98}\)
given mass of solute = 18 x 98 = 1764 g
mass of solvent = 1800 - 1764 = 36 g
m = \(\frac{\text{no of moles of solute}}{\text{mass of solvent (in g)}}\) x 1000
m = \(\frac{18}{36}\) x 1000
m = 500