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For the given equation of charge $Q=3t^2+6t$, where Q is in coulomb and t is time in sec, the initial value of current is: |
0 A 2 A 6 A 9 A |
6 A |
The correct answer is Option (3) → 6 A The current $I(t)$ is the rate of charge $Q(t)$ with respect to time, $I(t)=\frac{dQ}{dt}=\frac{d}{dt}(3t^2+6t)=6t+6$ Now, Initially $t=0s$ $∴I(0)=6(0)+6=6A$ |
