For the given equation of charge $Q=3t^2+6t$, where Q is in coulomb and t is time in sec, the initial value of current is:
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → 6 A
The current $I(t)$ is the rate of charge $Q(t)$ with respect to time,
$I(t)=\frac{dQ}{dt}=\frac{d}{dt}(3t^2+6t)=6t+6$
Now, Initially $t=0s$
$∴I(0)=6(0)+6=6A$