Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Ray Optics

Question:

If the tube length of astronomical telescope is 105 cm and magnifying power is 20 for normal setting, calculate the focal length of the objective

Options:

100 cm

10 cm

20 cm

25 cm

Correct Answer:

100 cm

Explanation:

$L=f_0+f_e=105cm$ and $M=\frac{f_0}{f_e}=20$

$⇒f_0=100cm$ and $f_e=5cm$