Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Continuity and Differentiability

Question:

Options:

a

b

c

d

Correct Answer:

c

Explanation:

$x∈(2,3)⇒2<x<3$

so $|x-3|=3-x$

$|x-2|=x-2$

so $|x-3|+|x-2|=1$