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The value of remainder when $(128 × 138 × 24 × 50 × 236 ×19)$ is divided by 9 is : |
8 7 5 0 |
0 |
The correct answer is Option (4) → 0 $128→1+2+8=11→11\,mod\,9=2$ $138→1+3+8=11→12\,mod\,9=3$ $24→2+4=6→6\,mod\,9=6$ $50→5+0=5→5\,mod\,9=5$ $236→2+3+6=11→11\,mod\,9=2$ $19→1+9=10→10\,mod\,9=1$ $⇒(2×3×6×5×2×1)\,mod\,9$ $⇒2×3=6$ $⇒6×6=36≡0\,mod\,9$ |
