The value of remainder when
$(128 × 138 × 24 × 50 × 236 ×19)$ is divided by 9 is :
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → 0
$128→1+2+8=11→11\,mod\,9=2$
$138→1+3+8=11→12\,mod\,9=3$
$24→2+4=6→6\,mod\,9=6$
$50→5+0=5→5\,mod\,9=5$
$236→2+3+6=11→11\,mod\,9=2$
$19→1+9=10→10\,mod\,9=1$
$⇒(2×3×6×5×2×1)\,mod\,9$
$⇒2×3=6$
$⇒6×6=36≡0\,mod\,9$