Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Semiconductors and Electronic Devices

Question:

In a common emitter circuit if VCC is changed by 0.2 V, collector current changes by $4 × 10^{–3} mA$. The output resistance will be:

Options:

10 kΩ

30 kΩ

50 kΩ

70 kΩ

Correct Answer:

50 kΩ

Explanation:

$R=\frac{Δ_{knee}}{ΔI_{ce}}=\frac{0.2}{0.004×10^{-3}}=50 kΩ$