Target Exam

CUET

Subject

Maths. Section B1

Chapter

Continuity and Differentiability

Question:

Discuss the continuity of the function $f$ given by $f(x) = x^3 + x^2 - 1$.

Options:

Continuous only at $x = 0$ and $x = 1$.

Discontinuous at $x = -1$.

Continuous at every real number.

Discontinuous where the derivative is zero.

Correct Answer:

Continuous at every real number.

Explanation:

The correct answer is Option (3) → Continuous at every real number. ##

Clearly $f$ is defined at every real number $c$ and its value at $c$ is $c^3 + c^2 - 1$. We also know that

$\lim\limits_{x \to c} f(x) = \lim\limits_{x \to c} (x^3 + x^2 - 1) = c^3 + c^2 - 1$

Thus $\lim\limits_{x \to c} f(x) = f(c)$, and hence $f$ is continuous at every real number. This means $f$ is a continuous function.