A motor has an armature resistance $4 \Omega$. It is operating on 220 V. At its full speed, it develops a back emf of 200 V. The current in the armature when the motor is switched on will be:

55 A

The correct answer is Option (4) → 55 A

The calculate the current in the momentum when the motor is switched on,

$I=\frac{V-E_b}{R_α}$

where,

$V$ (Applied voltage) = 220 V

$E_b$ (Back emf) = 200 V

$R_α$ (Armature Resistance) = 4 Ω

$∴I=\frac{220-200}{4}=5A$