If $y=x^4-10$ and if x changes from 2 to

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Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Applications of Derivatives

Question:

If $y=x^4-10$ and if x changes from 2 to 1.99, then the changed value of y is approximately:

Options:

-0.32

0.32

6.32

5.68

Correct Answer:

5.68

Explanation:

The correct answer is Option (4) → 5.68

$y=x^4-10$

at $x=2,y=6$

so $Δy=\frac{dy}{dx}×Δx⇒(4x^2)_{x=2}×(0.01)$

$=0.32$

so $y'=y-Δy$

so $6-0.32=5.68$