The principal values of $cos^{-1}\left(-sin\frac{7\pi}{6}\right)$, is
Answer & explanation
Correct answer: option 3
We have
$cos^{-1}\left(-sin\frac{7\pi}{6}\right)= cos^{-1}\left(-sin\left(\pi +\frac{\pi}{6}\right)\right) = cos^{-1}\left(sin\frac{\pi}{6}\right)$
$=\frac{\pi}{2}-sin^{-1}\left(sin\frac{\pi}{6}\right)=\frac{\pi}{2}-\frac{\pi}{6}=\frac{\pi}{3}$