A box has 20 pens: 6 black, 9 blue and 5 red. Meena takes out one pen at random. Match List-I with List-II.
| List-I (Event) | List-II (Probability) | ||
|---|---|---|---|
| (A) | The pen is black | (I) | \(\frac{9}{20}\) |
| (B) | The pen is blue | (II) | \(\frac{1}{4}\) |
| (C) | The pen is red | (III) | \(\frac{7}{10}\) |
| (D) | The pen is not black | (IV) | \(\frac{3}{10}\) |
Choose the correct answer from the options given below:
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → (A)-(IV), (B)-(I), (C)-(II), (D)-(III)
Each of the 20 pens is equally likely to be taken. Probability = favourable pens \(\div\) 20.
(A) Black: \(\frac{6}{20}=\frac{3}{10}\) → (IV)
(B) Blue: \(\frac{9}{20}\) → (I)
(C) Red: \(\frac{5}{20}=\frac{1}{4}\) → (II)
(D) Not black (blue or red): \(\frac{9+5}{20}=\frac{14}{20}=\frac{7}{10}\) → (III)
So the matching is (A)-(IV), (B)-(I), (C)-(II), (D)-(III).