The correct answer is Option (1) →
Reason:
In D(+)-glucose, the Fischer projection has:
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CHO at the top and CH₂OH at the bottom
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The –OH group on the penultimate carbon (C-5) is on the right, which defines the D-configuration
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The correct sequence of –OH groups from C-2 to C-5 is:
Right – Left – Right – Right
Only Option 1 shows this correct arrangement, so it represents D(+)-glucose. |
