Two men A and B start from Delhi and Agra at the same time towards each other. After meeting on the way they cover their remaining journey in 7\(\frac{1}{9}\) hrs and 6\(\frac{1}{4}\) hrs respectively. Find the speed (in km/hr) of A, if the difference of their speed is 40 km/hr.

600

7\(\frac{1}{9}\) = \(\frac{64}{9}\)

6\(\frac{1}{4}\) = \(\frac{25}{4}\)

\(\frac{S_{A} }{S_{B}}\) = \(\sqrt{\frac{t_{B}}{t_{A}}}\) \(\Rightarrow \) \(\sqrt{\frac{25/4}{64/9}}\) \(\Rightarrow \)\(\frac{15}{16}\)

Difference = 1R = 40 km/hr

Speed of A \(\Rightarrow \) 15R \(\longrightarrow \) 15× 40 km/h = 600km/hr.