Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Current Electricity

Question:

A voltmeter of resistance 998Ω is connected across a cell of emf 2 V and internal resistance 2Ω . The potential difference across the voltmeter is :

Options:

1.99 V

3.5 V

5 V

6 V

Correct Answer:

1.99 V

Explanation:

From Ohm’s law,

$i=\frac{E}{R+r}=\frac{2}{998+2}=2 \times 10^{-3} A$

Potential difference across the voltmeter is V = iR = (2 × 10-3) × 998 = 1.996 V