A voltmeter of resistance 998Ω is connected across a cell of emf 2 V and internal resistance 2Ω . The potential difference across the voltmeter is :
Answer & explanation
Correct answer: option 1
From Ohm’s law,
$i=\frac{E}{R+r}=\frac{2}{998+2}=2 \times 10^{-3} A$
Potential difference across the voltmeter is V = iR = (2 × 10-3) × 998 = 1.996 V