CUET Preparation Today
CUET
-- Applied Mathematics - Section B2
Numbers, Quantification and Numerical Applications
$(8×14)$ in 12 hours clock is :
4 o' clock
8 o' clock
6 o' clock
2 o' clock
The correct answer is Option (1) → 4 o' clock
$8×14=112$
$112/12=9$ remainder 4
$⇒\text{112 mod 12 = 4}$
