The energy liberated on complete fission of 1 kg of ₉₂U²³⁵ is (Assume 200 MeV energy is liberated on fission of 1 nucleus)

$8.2 × 10^{13} J$

Mass of a uranium nucleus = $92 × 1.6725 × 10^{-27}+143 × 1.6747 × 10^{-27}$

$=393.35 × 10^{-27} kg$

Number of nuclei in the given mass = $\frac{1}{393.35 × 10^{-27}}=2.542 × 10^{24}$

Energy released = $200 × 2.542 × 10^{24} MeV$

= $5.08 × 10^{26} MeV = 8.135 × 10^{13} \mathrm{~J}=8.2 × 10^{13} \mathrm{~J}$