The energy liberated on complete fission of 1 kg of 92U235 is (Assume 200 MeV energy is liberated on fission of 1 nucleus)
Answer & explanation
Correct answer: option 3
Mass of a uranium nucleus = $92 × 1.6725 × 10^{-27}+143 × 1.6747 × 10^{-27}$
$=393.35 × 10^{-27} kg$
Number of nuclei in the given mass = $\frac{1}{393.35 × 10^{-27}}=2.542 × 10^{24}$
Energy released = $200 × 2.542 × 10^{24} MeV$
= $5.08 × 10^{26} MeV = 8.135 × 10^{13} \mathrm{~J}=8.2 × 10^{13} \mathrm{~J}$