The moment of inertia of a thin uniform rod of mass M and length L about an axis passing through its midpoint perpendicular to its length is I₀. Its moment of inertia about an axis passing through one of its ends and perpendicular to its length is : 

\(I_o + \frac{ML^2}{4}\)

According to theorem of parallel axes

\(I = I_{CM} + Md^2\)

where

I_CM: moment of inertia of given rod is about an axis passing through centre of mass

I_CM = Io 

d = \(\frac{L}{2}\) 

\(I = I_{CM} + M(\frac{L}{2})^2\) 

\(I = I_{o} + M(\frac{L^2}{4})\)