Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Relations and Functions

Question:

The domain and range of the function $f(x)=\log_2\frac{\sin x-\cos x+3\sqrt{2}}{\sqrt{2}}$ are given by

Options:

$D_f=(-∞,∞),R_f=[1,2]$

$D_f=(-∞,0)∪(0,∞),R_f=[-1,1]$

$D_f=(0,∞),R_f=[1,2]$

none of these

Correct Answer:

$D_f=(-∞,∞),R_f=[1,2]$

Explanation:

$\frac{\sin x+\cos x}{\sqrt{2}}+3=\sin(x-π/4)+3$

so $-1≤\sin(x-π/4)≤1$

$⇒2≤(\sin(x-π/4)+3)≤4$  $⇒x ∈ R=(-∞,∞)$ = Domain

$1≤\log_2(\sin(x-π/4)+3)≤2$

⇒ Range = [1, 2]