Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Electromagnetic Waves

Question:

A plane electromagnetic wave of intensity 10 Wm−2 strikes a small mirror of area 20 cm2 , held perpendicular to the approaching wave. The radiation force on the mirror will be

Options:

6.6 × 10−11 N

1.33 × 10−11 N

1.33 × 10−10 N

6.6 × 10−10 N

Correct Answer:

1.33 × 10−10 N

Explanation:

Radiation force=momentum transferred per sec by electromagnetic wave to the mirror

$=\frac{2S_{av}A}{c}=\frac{2×(10)×(20×10^{-4})}{(3×10^8)}$

$=1.33 × 10^{-10} N$