O is the incentre of the triangle PQR. If angle POR = 140 degree, then what is the angle PQR?

100 degree

According to the concept,

\({90}^\circ\) + \(\angle\)PQR/2 = \({140}^\circ\)

⇒ \(\angle\)PQR/2 = \({140}^\circ\) - \({90}^\circ\)

⇒ \(\angle\)PQR/2 = \({50}^\circ\)

⇒ \(\angle\)PQR = \({100}^\circ\)

Therefore, \(\angle\)PQR is \({100}^\circ\)