Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Numerical Ability

Topic

Percentages

Question:

There is a continuous growth in the population of a village at the rate of 5% per annum. If its present population is 18522, what was the population of the village 3 years ago?

Options:

17500

16400

16000

17200

Correct Answer:

16000

Explanation:

Let population 3 years ago = x

According to question ,

x × \(\frac{105}{100}\) × \(\frac{105}{100}\) × \(\frac{105}{100}\) = 18522

 x = 18522 × \(\frac{20}{21}\) × \(\frac{20}{21}\) × \(\frac{20}{21}\)

x = 16000

So , population 3 years ago = 16000