Practicing Success
There is a continuous growth in the population of a village at the rate of 5% per annum. If its present population is 18522, what was the population of the village 3 years ago? |
17500 16400 16000 17200 |
16000 |
Let population 3 years ago = x According to question , x × \(\frac{105}{100}\) × \(\frac{105}{100}\) × \(\frac{105}{100}\) = 18522 x = 18522 × \(\frac{20}{21}\) × \(\frac{20}{21}\) × \(\frac{20}{21}\) x = 16000 So , population 3 years ago = 16000 |