Practicing Success
Practicing Success
CUET Preparation Today
If $A=\left[\begin{array}{ll}2 & 4 \\ 4 & 3\end{array}\right], X=\left[\begin{array}{l}n \\ 1\end{array}\right], B=\left[\begin{array}{c}8 \\ 11\end{array}\right]$ and $A X=B$, then the value of $n$ will be: |
0 1 2 not defined |
2 |
The correct answer is Option (3) → 2 |
