What is the average of the squares of the first five natural numbers?
Answer & explanation
Correct answer: option 4
Average of squares of Firs n numbers = \(\frac{(n+1)(2n+1)}{6}\)
Average of squares of first 5 numbers = \(\frac{(5+1)(10+1)}{6}\)
= \(\frac{(6)(11)}{6}\) = 11