What is the average of the squares of the first five natural numbers?

11.5 10 12.5 11

11

Average of squares of Firs  n numbers = \(\frac{(n+1)(2n+1)}{6}\)  Average of squares of first 5 numbers = \(\frac{(5+1)(10+1)}{6}\) = \(\frac{(6)(11)}{6}\)  = 11