X can do a work in 3 days, Y does three times the same work in 8 days, and Z does five times the same work in 12 days.If they have to work together for 6 hours in a day, then in how much time can they complete the work?

5 hours 20 minutes

X = 3 days x 6 = 18

Y = \(\frac{8}{3}\) days x 6 = 16

Z = \(\frac{12}{5}\) days x 6 = \(\frac{72}{5}\)

⇒ So, A + B +C will do the work in = \(\frac{144}{27}\) =\( { 5}_{27 }^{9 } \) = \( { 5}_{3 }^{1 } \) = 5 hours 20 minutes.

Therefore, they can complete the work in 5 hours and 20 minutes by working 6 hours a day.